Sizing a heat exchanger from the log mean temperature difference
Why the arithmetic temperature difference gives the wrong area, and how the log mean fixes it.
The engineering question
The exchanger computed from the average temperature difference is too small. What is the correct driving temperature difference?
Worked example
The figures below were produced by running the LMTD Calculator with the same inputs — during the build, from its authoritative engine.
| LMTD | 32.4358 °C |
|---|---|
| Required heat transfer area | 25.6918 m² |
| Hot-side temperature drop | 30 °C |
| Cold-side temperature rise | 25 °C |
| Correction factor (F) | 1 |
| Assessment | LMTD 32.4 °C (counter-flow, F = 1.0) → heat-transfer area ≈ 25.7 m² for the 500 kW duty. |
- Terminal differences are hot inlet less cold outlet, and hot outlet less cold inlet.
- The log mean of those two differences is the true driving force.
- Area is duty divided by U, the correction factor and the log mean difference.
Sanity check
LMTD always lies between the two terminal differences. A value outside that range means the temperatures have been mixed up.
Tools for this problem
These are the EngiMetric calculators that compute the numbers in this topic. Each one shows its formula, its units and its limits rather than returning a bare result.
Engineering review required
This topic supports professional engineering work; it does not replace a sealed design. The result depends on site data, the governing standard and engineering judgement, and should be confirmed by a competent engineer before it is built.
References & standards
- TEMA — heat exchanger standards and correction factors
- Incropera & DeWitt — heat transfer
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