Construction Engineering Verified Calculator

LMTD Calculator

Log mean temperature difference for a counter-flow heat exchanger and the heat transfer area it implies.

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Geometry-based calculation.Counter-flow log-mean temperature difference with a correction factor of 1.0. Multipass and cross-flow arrangements need their F value from the appropriate charts.

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What this calculator does

Heat exchanger sizing depends on the log-mean temperature difference, and using the arithmetic mean instead can over- or under-size a exchanger badly. This calculator computes the true counter-flow LMTD and, given a duty and an overall U-value, the heat transfer area you need.

How to use it

  1. Enter the four terminal temperatures: hot in, hot out, cold in and cold out.
  2. The calculator rejects cross-flow terminal conditions, because counter-flow LMTD does not apply there.
  3. Enter the heat duty in kW and the overall U-value in W/m²·K to get the required area.
  4. For shell-and-tube multipass exchangers apply the correction factor from TEMA before ordering.

Governing formula

Governing Formula
ΔT_lm = (ΔT₁ − ΔT₂) / ln(ΔT₁/ΔT₂) ; A = Q/(U·F·ΔT_lm)

Where:

  • ΔT₁ = Hot inlet minus cold outlet [°C]
  • ΔT₂ = Hot outlet minus cold inlet [°C]
  • Q = Heat duty [kW]
  • U = Overall heat transfer coefficient [W/m²·K]

Worked example — 80 → 50 °C hot water cooling against 20 → 45 °C

The figures below were produced by running this page's own engine with the example inputs (Hot fluid inlet (°C), Hot fluid outlet (°C), Cold fluid inlet (°C), Cold fluid outlet (°C), Heat duty (kW), Overall heat transfer coefficient (U) (W/m²·K)). If the calculator returns something different for the same numbers, that is a bug, not a rounding difference.

Expected results for the worked example
LMTD32.44 °C
Required heat transfer area25.69 m²
Hot-side temperature drop30 °C
Cold-side temperature rise25 °C
Correction factor (F)1
AssessmentLMTD 32.4 °C (counter-flow, F = 1.0) → heat-transfer area ≈ 25.7 m² for the 500 kW duty.
  1. ΔT₁ = 80 − 45 = 35 °C and ΔT₂ = 50 − 20 = 30 °C.
  2. LMTD = (35 − 30) / ln(35/30) ≈ 32.5 °C.
  3. With U = 600 W/m²·K and a 500 kW duty the required area is about 25.6 m².

Assumptions & limitations

Engineering calculation. Counter-flow log-mean temperature difference with a correction factor of 1.0. Multipass and cross-flow arrangements need their F value from the appropriate charts.

  • Counter-flow only; a cross-flow or multi-pass arrangement needs a correction factor below 1 and a different approach.
  • U-value depends on the fluids, fouling films and flow arrangement — use the value for your duty, not a handbook average.
  • Assumes no heat loss to the surroundings and constant flow rates.

This tool supports professional engineering work; it does not replace a sealed design. Confirm every result against the applicable standard and a licensed engineer before it is built.

References & standards

  • TEMA — Standards for heat exchangers, correction factors.
  • Incropera & DeWitt, Fundamentals of Heat and Mass Transfer.
  • ASME B31.3 — process piping and exchanger design.
Engineering Disclaimer & Verification Notice

This calculator provides preliminary engineering estimates for informational and planning purposes. Actual reverse osmosis / engineering system performance depends on site conditions, feed-water chemistry, membrane characteristics, operating pressure, temperature, recovery limits, fouling/scaling potential, and system design. Verify results using project-specific data, manufacturer projections, and applicable engineering standards before final design or operation.